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0.01x^2-0.11x+0.01=0
a = 0.01; b = -0.11; c = +0.01;
Δ = b2-4ac
Δ = -0.112-4·0.01·0.01
Δ = 0.0117
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.11)-\sqrt{0.0117}}{2*0.01}=\frac{0.11-\sqrt{0.0117}}{0.02} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.11)+\sqrt{0.0117}}{2*0.01}=\frac{0.11+\sqrt{0.0117}}{0.02} $
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